Describe how you would prepare 400.0 mL of C12H22O11 0.100 M from 2.00 L of C12H22O11...

Question

Question

Describe how you would prepare 400.0 mL of C₁₂H₂₂O₁₁ 0.100 M from 2.00 L of C₁₂H₂₂O₁₁ 1.50 M.

science chemistry

Answer 1

Answer #1

according to dilution law

M1V1 = M2V2

M1 = 1.50 M , V1 = ?

M2 = 0.1 M , V2 = 400 mL

V1 = (M2V2 / M1)

V1 = (0.1 x 400 / 1.50)

V1 = 26.67 mL

take 26.67 mL 1.50 M solution diluted to 400 mL with water. we will get desiered solution

Answer 2

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