represent -2048.75 in IEEE-754 single precision format.
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Converting 2048.75 to binary
Convert decimal part first, then the fractional part
> First convert 2048 to binary
Divide 2048 successively by 2 until the quotient is 0
> 2048/2 = 1024, remainder is 0
> 1024/2 = 512, remainder is 0
> 512/2 = 256, remainder is 0
> 256/2 = 128, remainder is 0
> 128/2 = 64, remainder is 0
> 64/2 = 32, remainder is 0
> 32/2 = 16, remainder is 0
> 16/2 = 8, remainder is 0
> 8/2 = 4, remainder is 0
> 4/2 = 2, remainder is 0
> 2/2 = 1, remainder is 0
> 1/2 = 0, remainder is 1
Read remainders from the bottom to top as 100000000000
So, 2048 of decimal is 100000000000 in binary
> Now, Convert 0.75000000 to binary
> Multiply 0.75000000 with 2. Since 1.50000000 is >= 1. then add 1 to result
> Multiply 0.50000000 with 2. Since 1.00000000 is >= 1. then add 1 to result
> This is equal to 1, so, stop calculating
0.75 of decimal is .11 in binary
so, 2048.75 in binary is 100000000000.11
-2048.75 in simple binary => 100000000000.11
so, -2048.75 in normal binary is 100000000000.11 => 1.0000000000011 * 2^11
single precision:
--------------------
sign bit is 1(-ve)
exp bits are (127+11=138) => 10001010
Divide 138 successively by 2 until the quotient is 0
> 138/2 = 69, remainder is 0
> 69/2 = 34, remainder is 1
> 34/2 = 17, remainder is 0
> 17/2 = 8, remainder is 1
> 8/2 = 4, remainder is 0
> 4/2 = 2, remainder is 0
> 2/2 = 1, remainder is 0
> 1/2 = 0, remainder is 1
Read remainders from the bottom to top as 10001010
So, 138 of decimal is 10001010 in binary
frac bits are 00000000000110000000000
so, -2048.75 in single-precision format is 1 10001010 00000000000110000000000
in hexadecimal it is 0xC5000C00
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Assume all values are stored in a single precision IEEE-754 format. Calculate 2.5*10-1 divided by: a. 1.25*10-1 b. 0 Show all your steps and write your answers in both the single-precision floating-point format and in decimal.
Please show steps
EXERCICE4 The following real numbers are given in single precision (ieee-754 floating point) format. Negate each of them. Single Precision FP Inverse (negated) value in single precision FP Ox3FCO0000 OxAFC00000 0x43806000 0xC3906000 0x41200000 0xF1200000 0x3F7F0000 EXERCICE 5 Express the following real numbers (single precision ieee-754 floating point) in decimal notation Single Precision FP Value in base 10 0x3FC00000 0xBFC00000 0x43806000 0xC3806000 0x41200000 0xC1200000 0x3F7F0000
(2 pts) Express the base 10 numbers 16.75 in IEEE 754 single-precision floating point format. Express your answer in hexadecimal. Hint: IEEE 754 single-precision floating-point format consists of one sign bit 8 biased exponent bits, and 23 fraction bits) Note:You should show all the steps to receive full credits) 6.7510 Type here to search