Let the function fun be defined as int fun(int *k) { *k - = 2; return...
Let the function fun be defined as
int fun(int *k) {
*k - = 2;
return 4 * (*k) +2 ;
}
Suppose fun is used in a program as follows:
void main() {
int i = 16, j = 16, sum1, sum2;
sum1 = (i / 2) + fun(&i);
sum2 = fun(&j) + (j / 2);
}
What is the values of sum1 and sum2
a. If the operands in the expressions are evaluated from left to
right
sum1 = sum2 =
b. If the operands in the expressions are evaluated from right to
left
sum1 = sum2 =
Homework Answers
Thanks for the question.
Here is the completed code for this problem. Let me know if you
have any doubts or if you need anything to change.
Thank You !!
================================================================================================
a. If the operands in the expressions are evaluated from left to
right
sum 1 will be : 66
first i/2 will be evaluated 16/2 = 8
fun(&i) = 4*14+2 = 58
so sum1 will be 8+58 = 66
sum 2 will be : 65
first fun(&j) will be evaluated which is equal to 4*14+2 = 58
and in this step j is reduced to 14
then j/2 will be evaluated which is equal to 14/2 = 7
so sum2 will be 58+7=65
===========================================================================================
b. If the operands in the expressions are evaluated from right to left
sum 1 will be : 65
first fun(&i) will be evaluated which is equal to 4*14+2 =
58 and in this step i is reduced to 14
then i/2 will be evaluated which is equal to 14/2 = 7
so sum1 will be 58+7=65
sum 2 will be : 66
first j/2 will be evaluated 16/2 = 8
fun(&j) = 4*14+2 = 58
so sum2 will be 8+58 = 66
=====================================================================================
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