Calculate the minimum resistance to limit the gate current (in the worst case) to 70.71% IGM on a 2N6508 SCR that is on a 100V RMS / 50Hz line. (Use a protection diode on the gate circuit. )
According to the datasheet of 2N6058 SCR maximum value of IGM is 2 Amp and we have to limit it to the 70.71%.
So the maximum current would be 2*0.7071=1.4142 Amp
Now the minimum resistance would be = (V/I)
R=Vrms/I =100/1.4142 = 70.71 ohm.
I u have any doubt regarding solution then please let me know in comments.
Calculate the minimum resistance to limit the gate current (in the worst case) to 70.71% IGM...
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