Question

AgBr is almost completely soluble in water, Ksp = 7.7 x 10^-13. However, AgBr reacts with...

AgBr is almost completely soluble in water, Ksp = 7.7 x 10^-13. However, AgBr reacts with ammonia to form a complex ion, Ag(NH3)2 +1. Kf for Ag(NH3)2 +1 = 1.7 x10^7. Based on the information above, what will be the equilibrium constant for the following reaction? AgBr(s) + 2NH3(aq) <---> Ag(NH3)2+1(aq) + Br-1(aq)

0 0
Add a comment Improve this question Transcribed image text
Request Professional Answer

Request Answer!

We need at least 10 more requests to produce the answer.

0 / 10 have requested this problem solution

The more requests, the faster the answer.

Request! (Login Required)


All students who have requested the answer will be notified once they are available.
Know the answer?
Add Answer to:
AgBr is almost completely soluble in water, Ksp = 7.7 x 10^-13. However, AgBr reacts with...
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Similar Homework Help Questions
ADVERTISEMENT
Free Homework Help App
Download From Google Play
Scan Your Homework
to Get Instant Free Answers
Need Online Homework Help?
Ask a Question
Get Answers For Free
Most questions answered within 3 hours.
ADVERTISEMENT
ADVERTISEMENT