
Given the following reactions, AgBr(s) = Ag+ (aq) + Br(aq) Ksp = 5.8 x 10-13 Ag+...
Given the following reactions, AgBr(s) Ag (aq) + Br(aq) Ag*(aq)2 CN (aq)=Ag(CN)2(aq) K 1.2E+21 determine the equilibrium constant for the reaction below AgBr(s)2 CN-(aq)= Ag(CN)2 (aq) Brr(aq) Ksp 5.4E-13
Item 10: Question (10 pts.) Given the following reactions, AgBr(s) = Ag+(aq) + Br-(aq) Kap = 5.4E-13 Ag+ (aq) + 2 CN-(aq) — Kp = 1.2E+21 Ag(CN), (aq) determine the equilibrium constant for the reaction below. AgBr(s) + 2 CN- (aq) = Ag(CN)2 (aq) + Br(aq) Submit Submit and Next O: Mark this question for later review. - Skip to Previous
AgBr is almost completely soluble in water, Ksp = 7.7 x 10^-13. However, AgBr reacts with ammonia to form a complex ion, Ag(NH3)2 +1. Kf for Ag(NH3)2 +1 = 1.7 x10^7. Based on the information above, what will be the equilibrium constant for the following reaction? AgBr(s) + 2NH3(aq) <---> Ag(NH3)2+1(aq) + Br-1(aq)
the equilibrium constant for the reaction AgBr(s)<—>Ag(aq)+Br-(aq) is the solubility product constant Ksp=7.7*10^-13 at 25 degrees C calculate the delta G for the reaction [Ag]= 1.0*10^-2 M and [Br]= 1.0*10^3 M. is the reaction spontaneous or nonspontaneous at these concentrations
Consider the following information at 25 ºC: AgBr(s) + e- → Ag(s) + Br-(aq) Eº(AgBr(s),Ag(s)) = 0.07133 V Ag+(aq) + e- → Ag(s) Eº(Ag+(aq),Ag(s)) = 0.7996 V What is the value of the solubility product equilibrium constant Ksp(AgBr) of silver bromide? AgBr(s) ↔ Ag+(aq) + Br-(aq) Ksp(AgBr)
Given that Ksp for AgI(s) = 8.3 × 10−17 and Kf for [Ag(CN)2]− = 1.0 × 1021 at 25°C, what is the ΔG° for the following reaction at the same temperature? AgI(s) + 2 CN−(aq) ⇌ [Ag(CN)2]−(aq) + I−(aq) A. –300 kJ/mol B. –248 kJ/mol C. –152 kJ/mol D. –28 kJ/mol E. +13 kJ/mol
Question 22 (5 points) Given the following half reactions: - AgBr(s) + e- Ag+ (aq) + e- Ag(s) + Br- (aq) E° = 0.07V → Ag (s) E° = 0.80V - Calculate the Ksp for PbSO4 at 25 degrees C. Please enter your answer in scientific notation, such as 1.2E10 or 1.2E-10 and keep two significant figures.
What is the solubility of AgBr in 0.05 M NaCN? Ksp(AgBr) = 5.0 x 10-13 and Kr(Ag(CN)2') = 1.0 x 1021 LIS-ntion of drico Coel is always spontaneous, never
1. Given the two equilibria below, Ag(NH3)2(aq) = Agt(aq) + 2NH3(aq); Kd = 5.9 x 10-8 AgBr(s) Ag+(aq) + Br" (aq); Ksp = 5 x 10-13 what is K, for the following equilibrium? AgBr(s) + 2NH3(aq) = Ag(NH3)2(aq) + Br" (aq) a. 3 x 10-20 b.2.7 x 100 c. 7.2 x 10-11 d. 8.5 x 10-6 e. 1.2 x 105
Zn2+(aq) + 4Cn-(aq) ---> [Zn(CN-)4]2-(aq) Kf=2.1x1019 Given that the Ksp for ZnS is 2.0x10-25, use the Kf from the previous to find the equilibrium constant for the following reaction: ZnS(s) + 4CN-(aq) ---> [Zn(CN-)4]2-(aq) + S-2(aq)