HomeworkLib
Question

An object is 25.0 cm from a diverging lens and the object is 1.30 cm tall....

An object is 25.0 cm from a diverging lens and the object is 1.30 cm tall. What is the position and height of the image if the focal length of the lens is -32.0 cm?

A) The object is at -0.0713 cm and the height of the image will be 0.728 cm inverted. B) The object is at -14.0 cm and the height of the image will be 0.00371 cm inverted. C) The object is at -0.0713 cm and the height of the image will be 0.00371 cm upright. D) The object is at -14.0 cm and the height of the image will be 0.728 cm upright.

science   physics   
0 0
Add a comment Improve this question Transcribed image text
Next > < Previous
Sort answers by oldest

Homework Answers

Answer #1

0 0
Add a comment
Know the answer?
Add Answer to:
An object is 25.0 cm from a diverging lens and the object is 1.30 cm tall....
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Log In

Sign Up

Not the answer you're looking for? Ask your own homework help question. Our experts will answer your question WITHIN MINUTES for Free.
Similar Homework Help Questions

  • A 5 cm tall object is 20 cm in front of a diverging lens with a...

    A 5 cm tall object is 20 cm in front of a diverging lens with a focal length of 10 cm. a) What is the location of the image?  cm b) What is the height of the image?  cm c) The image is:real or virtual     d) The image is: inverted or upright    

  • A 20 cm tall object is located 70 cm away from a diverging lens that has...

    A 20 cm tall object is located 70 cm away from a diverging lens that has a focal length of 20 cm. Use a scaled ray tracing to answer parts a-d. a. Is the image real or virtual? b. Is the image upright or inverted? c. How far from the lens is the image? d. What is the height of the image? e. Now use the thin lens equation to calculate the image distance and the magnification equation to determine...

  • A 4-cm tall object is placed 59.2 cm from a diverging lens having a focal length...

    A 4-cm tall object is placed 59.2 cm from a diverging lens having a focal length of -29.5 cm. a) Is the image produced by this lens virtual or real? b) Is the image inverted or upright? c) Is the image on the same side of the lens as the object or on the opposite side as the object? d) Where is the image located? (Please provide the magnitude of the position, no negative numbers) e) How tall is the...

  • A 2.0-cm-tall object is 17.5 cm in front of a diverging lens that has a -25...

    A 2.0-cm-tall object is 17.5 cm in front of a diverging lens that has a -25 cm focal length. 1. Calculate the image position. 2. Calculate the image height. Type a positive value if the image is upright and a negative value if it is inverted.

  • A 3.0-cm-tall object is 24 cm in front of a diverging lens that has a -30...

    A 3.0-cm-tall object is 24 cm in front of a diverging lens that has a -30 cm focal length. 1. Calculate the image position. 2. Calculate the image height. Type a positive value if the image is upright and a negative value if it is inverted.

  • A 4.0 cm tall object is placed 50.0 cm from a diverging lens having a focal...

    A 4.0 cm tall object is placed 50.0 cm from a diverging lens having a focal length of magnitude 20.0cm. a. What is the location of the image? b. What is the magnification of the image? c. Is the image inverted or upright? d. Is the image virtual or real?

  • A 2.5-cm-tall object is 90cm in front of a diverging lens that has a -45cm focal...

    A 2.5-cm-tall object is 90cm in front of a diverging lens that has a -45cm focal length. A) Calculate the image position. B) Calculate the image height. Type a positive value if the image is upright and a negative value if it is inverted. Please show all your formulas and work!

  • 2) A diverging lens is placed 20. cm away from an object, 80. cm from the...

    2) A diverging lens is placed 20. cm away from an object, 80. cm from the diverging lens is a converging lens whose focal length is 25 cm. 35. cm from the converging lens is a screen showing an image of the object. a) What is the focal length of the diverging lens? f = 25. cm o *20. cm → 80. cm + 35 cm → b) What type of image is it? Circle one Real or Virtual c)...

  • Suppose a 1.5 cm tall object is placed 3.50 cm in front of a diverging lens...

    Suppose a 1.5 cm tall object is placed 3.50 cm in front of a diverging lens with focal length -2.00 cm. Draw a ray diagram that accurately shows the image. The image is {a. upright b. inverted}. The image is {a. real b. virtual}.

  • A 3.0-cm-tall object is 20 cm in front of a diverging lens that has a-30 cm...

    A 3.0-cm-tall object is 20 cm in front of a diverging lens that has a-30 cm focal length Part A Calculate the image position Express your answer to two significant figures and include the appropriate units. Enter positive value if the image is on the other side from the lens and negative value if the image is on the same side. HA ON? Value Units Submit Request Answer Part B Calculate the image height Express your answer to two significant...

ADVERTISEMENT
Free Homework Help App
Download From Google Play
Scan Your Homework
to Get Instant Free Answers
Need Online Homework Help?
Ask a Question
Get Answers For Free
Most questions answered within 3 hours.
ADVERTISEMENT
ADVERTISEMENT