Find the margin of error from the given 95% confidence interval for the population proportion of patients who said “Drug X was effective in delivering pain relief.” 95% CI: (0.84, 0.96)
Group of answer choices
.03
.06
.12
.90
Solution :
Point estimate =
= (Lower confidence interval + Upper confidence interval ) / 2
Point estimate =
= (0.84+ 0.96)/ 2=0.9
Margin of error = E = Upper confidence interval -
= 0.96 - 0.9=0.06
Find the margin of error from the given 95% confidence interval for the population proportion of...
sample should be taken to provide a 95% confidence interval with a margin of error of .05? At 95% confidence, how large a sample should be taken to obtain a margin of error of .03 for the estimation of a population proportion? Assume that past data are not available for developing a planning value for p* 34.
7.1
Q6
find margin of error and confidence interval
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