In lab, we added 0.180g ethyl trans-cinnamate, 4 mL dicholormethane, and 1.2 equivalents of mCPBA (60%...
In lab, we added 0.180g ethyl trans-cinnamate, 4 mL dicholormethane, and 1.2 equivalents of mCPBA (60% by weight) to a vial. Then we rinsed the solid with 3 mL CH2Cl2, added 5 mL of 10% aqueous sodium sulfite and separated it in a separatory funnel, and then washed it with 5 mL of 5% aqueous sodium bicarbonate to remove any remaining acid. Finally, we dried the organic layer over CaCl2. We then removed the remaining CH2Cl2 using the rotary evaporator.
What is the reaction that occurred during this whole process and the mechanisms involved?
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In lab, we added 0.180g ethyl trans-cinnamate, 4 mL
dicholormethane, and 1.2 equivalents of mCPBA (60%...
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of a reactant or reagent compared to the # of moles of the
substrate. But I am confused on how to answer this question and why
the procedure would call for more NaI than Vanillin if Vanillin is
the substance needed substituted. Can you help?
Thanks!
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