How much would you have to dilute 1x108 E. coli cells/ml so that when you plate...

Question

Question

How much would you have to dilute 1x10⁸ E. coli cells/ml so that when you plate 200µl you obtain 200 E. coli cells on a LB Agar plate?

science biology

Answer 1

Answer #1

200 E. Coli cells in 200ul can be considered as 1000 cells in 1000ul.

Since we have 10⁸ cells per ml we have to dilute it make it upto 10³ Cells per ml.

Which means we have to dilute 10⁸ to 10³

This 10⁵ time dilution.

So add 10uL from 10⁸ Solution with 990 uL to dilute it to 10⁶

then add 10uL from 10⁶ Solution with 990 uL to dilute it to 10⁴

So add 100uL from 10⁴ Solution with 900 uL to dilute it to 10³

Simple take 200ul from diluted solution to take 200 E.Coli cells

Answer 2

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