The human body obtains 1095 kJ of energy from a candy bar. If this energy were used to vaporize water at 100.0 ∘C, how much water (in liters) could be vaporized? (Assume the density of water is 1.00 g/mL.)
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The human body obtains 1095 kJ of energy from a candy bar. If this energy were...
The human body obtains 1048 kJ from a candy bar. If this energy were used to vaporize water at 100 ∘C, how much water in liters could be vaporized? Assume that the density of water is 1.0 g/mL. The heat of vaporization of water at 100 ∘C is 40.7 kJ/mol. (Hint:Begin by using the enthalpy of vaporization of water to convert between the given number of kilojoules and moles of water.) Express your answer to three significant figures and include...
8. A typical candy bar has 35.0 g of glucose. The human body generates energy from glucose by the thermochemical equation provided below CH,204(s) + 6 02(g) → 6 CO2(g) + 6 H20(1) AH = -670 kcal How much energy is obtained from the digestion of a typical candy bar? Show your work Final Answer You are provided the following data: H2(g) → 2 Hg) Br(g) → 2 Br(g) H2(g) + Bra(g) → 2 HBr(g) AH = 436.4 kJ/mol AH...
If all of the energy from burning 430.0 g of propane (ΔHcomb,C3H8 = –2220 kJ/mol) is used to heat water, how many liters of water can be heated from 20.0°C to 100.0°C? (Assume that the density of water is 1.00 g/mL)
8. A typical candy bar has 35.0 g of glucose. The human body generates energy from glucose by the thermochemical equation provided below CaH2O(s) +6 0;(g) 6 CO:(g ) + 6 H2O(0) AH 670 kcal How much energy is obtained from the digestion of a typical candy bar? Show your work Final Answer 9. You are provided the following data: H2(g) 2 H(g) Br(g) 2 Br(g) H2(g) + Br(g)2 HBr(g) AH 436.4 kJ/mol AH 192.5 kJ/mol AH-72.4 kJ/mol Calculate AH...
Il See Periodic Table See Hin If all of the energy from burning 254.0 g of propane (AHcomb.cana = -2220 kJ/mol) is used to heat water, how many liters of water can be heated from 20.0°C to 100.0°C? (Assume that the density of water is 1.00 g/mL) L of water
Please write clearly and use sig figs. thanks in advance
8. A typical candy bar has 35.0 g of glucose. The human body generates energy from glucose by the thermochemical equation provided below C6H1206(S) + 6 O2(g) → 6 CO2(g) + 6 H2O(1) AH=-670 kcal How much energy is obtained from the digestion of a typical candy bar? Show your work Final Answer You are provided the following data: H2(g) → 2 H(g) Br(g) → 2 Br(g) H2(g) + Br2(g)...
The label on a candy bar says 480 Calories. Assuming a typical efficiency for energy use by the body, if a 62 person were to use the energy in this candy bar to climb stairs, how high could she go?
Question (2 points) See page 22 1st attempt See Periodic Table See Hint If all of the energy from burning 318.0 g of propane (A Hcomb.C3H8 --2220 kJ/mol) is used to heat water, how many liters of water can be heated from 20.0°C to 100.0°C? (Assume that the density of water is 1.00 g/ml) L of water < 07/11 D40 ENG 0 OF 11 QUESTIONS COMPLETED e here to search
Sodium hydroxide (NaOH) has a lattice energy of -887 kJ/mol and a heat of hydration of -932 kJ/mol. Part A How much solution could be heated to boiling by the heat evolved by the dissolution of 22.0 g of NaOH? (For the solution, assume a heat capacity of 4.0 J/g⋅∘C, an initial temperature of 25.0 ∘C, a boiling point of 100.0 ∘C, and a density of 1.05 g/mL.) Express your answer using two significant figures. V = mL
1. A system releases 654 kJ of heat and does 140 kJ of work on the surroundings. What is the change in internal energy of the system? 2. How much heat is required to warm 1.30 L of water from 26.0 ∘C to 100.0 ∘C? (Assume a density of 1.0g/mL for the water.) Express your answer using two significant figures..