The solubility of O2 in water is approximately 0.00380 g L-1 when the temperature is 25.0...

Question

Question

The solubility of O₂ in water is approximately 0.00380 g L^-1 when the temperature is 25.0 and the partial pressure of gaseous oxygen is 1.00 atm. What will the solubility of oxygen be if the oxygen pressure is readjusted to 1.00 x 10³ torr?

science chemistry

Answer 1

Answer #1

Solubility=KP

K is called henrys constant

P is the partial pressure

At constant temperature solubility is directly proportional to the partial pressure

S₁/S₂=P₁/P₂

P1= 1 atm

P2= 1000 torr= (1000/760) =1.31578947368 atm

S1=0.00380 g/L

S2=(S1*P2) /P1

S2=(0.00380 g.L^-1*1.315789 atm) /1 atm

S2=0.00499 g. L^-1

Answer 2

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