The drag force on falling box is described by FD=(1/2)ρACDv2, where ρ is the density of air, 1.2 kg/m3. The mass of the box is 12.0 g, and the effective area of the bottom of the box is 109 cm2. Assume a drag coefficient of 1.10
a) Determine the drag force on the box when it is falling at a speed of 1.21 m/s.
b) The box will reach terminal speed when the drag force on it is equal to its weight: (1/2)ρACDv2=mg. Estimate the terminal speed of the box.
The drag force on falling box is described by FD=(1/2)ρACDv2, where ρ is the density of...
A falling body on Earth will generally not fall at constant acceleration in reality, due to air resistance (or drag). The equation for the drag force Fd is Fd = 0.5 (Cd A) ρ v2 where Cd is the unitless drag coefficient of a body, A is its cross-sectional area, ρ is the density of the air, and v is the body's velocity with respect to the atmosphere.(b) Look up and then see if you can also calculate the terminal...
The mass density of air on Mars is ρ=0.016 kg/m3. The gravity on Mars is gMars= 3.7 m/s2. The mass density of air on earth under standard pressure and temperature conditions is ρ=1.225 kg/m3. A NASA mars probe weighs 1000 N on Earth. At terminal velocity, the weight of a falling object is equal to the drag force. Assume that the drag coefficient of the parachute used is constant, and has the same value on both Earth or Mars, and...
Calculate the terminal velocity for a pollen grain falling through the air using the drag force equation. Assume the pollen grain has a diameter of 7 µm and a density of 0.3 g/cm3. If this grain is released from the top of a tree (height 11 m), estimate the time it will take to fall to the ground. Hint: The pollen grain will reach its terminal velocity very quickly and will have this velocity for essentially the entire motion. Your...
A 78 kg skydiver can be modeled as a rectangular "box" with dimensions 21 cm × 41 cm × 170 cm . If he falls feet first, his drag coefficient is 0.80. What is his terminal speed if he falls feet first? Use ρ = 1.2 kg/m3 for the density of air at room temperature.
A spherical raindrop 1.9 mm in diameter falls through a vertical distance of 4150 m. Take the cross-sectional area of a raindrop = πr2, drag coefficient = 0.45, density of water to be 1000 kg/m3, and density of air to be 1.2 kg/m3. (a) Calculate the speed a spherical raindrop would achieve falling from 4150 m in the absence of air drag. _________ m/s (b) What would its speed be at the end of 4150 m when there is air...
1. A rocket is launched vertically from the Earth, and the thrust (pushing force) from the engines is directed upward, and has a magnitude of 5.00 x 106 N. The mass of the rocket is initially 2.00 x 105 kg. (a) What is the initial acceleration of the rocket, assuming you can neglect air resistance? (b) After the rocket has been in flight for a while, burning and exhausting a lot of fuel, its mass has decreased to 1.20 x 105 kg, and...
A 75 kg skydiver can be modeled as a rectangular "box" with dimensions 24 cm × 41 cm × 170 cm . If he falls feet first, his drag coefficient is 0.80. Part A What is his terminal speed if he falls feet first? Use ρ = 1.2 kg/m3 for the density of air at room temperature. Express your answer with the appropriate units.
The drag force on a cannonball falling through the air does not depend upon what factor? Group of answer choices the density of air the cannonball's cross-sectional area the cannonball's mass the cannonball's drag coefficient with air the cannonball's speed
A spherical raindrop 3.3 mm in diameter falls through a vertical distance of 4000 m. Take the cross-sectional area of a raindrop ,drag coefficient 0.45, density of water to be 1000 kg/m3, and density of air to be 1.2 kg/m3. (a) Calculate the speed a spherical raindrop would achieve falling from 4000 m in the absence of air drag 280 m/s (b) What would its speed be at the end of 4000 m when there is air drag? 1.091 What...
#4 and #5!!
4. A 55 kg box rests on a horizontal surfcion betwce the box and the surface is 0.30, and the coefficient of kinetic friction is 0.20. What horizontal force must be applied to the box to cause it to start sliding along the surface? 4 :0 ovit 5. A projectile is launched at ground level with an initial speed of 50.0 m/s at an angle of 300 above the horizontal. It strikes a target above the ground...