Aegilops cylindrica (2n=28) and Triticum vulgare (2n=42) are crossed. The resulting F1 plants from this cross...
Aegilops cylindrica (2n=28) and Triticum vulgare (2n=42) are crossed. The resulting F1 plants from this cross had 35 chromosomes. Examination of metaphase I in the F1 plants revealed the presence of 7 pairs of chromosomes (bivalents) and 21 unpaired chromosomes (univalents).
a. If the unpaired chromosomes segregate randomly, what possible chromosome numbers will appear in the gametes of the F1 plants?
b. What does the appearance of the bivalents in the F1 hybrids suggest about the origin of Triticum vulgare wheat?
Homework Answers
a) The answer will be 7 to 28.
Explanation: From each of the 7 pairs of chromosomes (bivalents), each gamete will receive 1 chromosome & thus will get 7 chromosomes in total. 21 unpaired chromosomes (univalent) can segregate randomly & each gamete has a possibility to receive from 0 to 21 chromosomes. Thus, possible chromosome numbers in the gametes of the F1 plants will be 7 to 28.
b) As we observed 7 bivalents in the F1 hybrids, these chromosomes are obtained from common ancestors of Aegilops cylindrica & Triticum vulgare. Additional chromosomes which are not paired are obtained in Triticum vulgare from other ancestors that aren't shared with Aegilops cylindrica.
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Aegilops cylindrica (2n=28) and Triticum vulgare (2n=42) are
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