Hemophilia is another example of a X-linked disease caused when a recessive allele (Xh) is expressed....
Hemophilia is another example of a X-linked disease caused when a recessive allele (Xh) is expressed. If a normal male reproduces with a heterozygous normal female, what are the expected genotypes and phenotypes? Will any of their daughters develop hemophilia? As in the previous question, you must also give the gender of the child in your genotype and phenotype descriptions here
Homework Answers
let the alleles be XH- normal, Xh- hemophilic
the genotype of the normal man is XHY and the genotype of the heterozygous woman is XHXh.
XHY * XHXh
| XH | Y | |
| XH | XHXH ( normal female) | XHY ( normal male) |
| Xh | XHXh ( carrier female, phenotypically normal) | XhY ( hemophilic male) |
the expected genotype and phenotypes are given in the punnet square.
the genotypes of the daughters are XHXh and XHXH both are phenotypically normal, for a female to develop hemophilia her genotype has to be XhXh here none of the daughters have XhXh genotype so all daughters are phenotypically normal.
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need help with 1 and 2 please.
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