A particular fruit's weights are normally distributed, with a
mean of 256 grams and a standard deviation of 9 grams.
The heaviest 5% of fruits weigh more than how many grams?
Give your answer to the nearest gram.
solution
Using standard normal table,
P(Z > z) = 5%
= 1 - P(Z < z) = 0.05
= P(Z < z ) = 1 - 0.05
= P(Z < z ) = 0.95
= P(Z < 1.64 ) = 0.95
z = 1.64 (using standard normal (Z) table )
Using z-score formula
x = z *
+
x= 1.64*9+256
x= 270.76
x=271
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