A mining company receives samples of ore every 5 minutes in a Poissonian way, to which...
Homework Answers
Given :
Arrival Rate (
)
or Average number of Ore sample arrivals/hour = 60/5 = 12
samples/hour
Service rate, 
or Average samples serviced per hour = 60/7 = 8.57
samples/hour
1) Average number of samples waiting in line for analysis
=
2/(-)
= 122/8.57(8.57-12)
= -4.89 samples
2) Average time a sample spends in a system = Average time
waiting in line + 1/
=
/(-)
+ 1/
= 12/8.57(8.57-12) + 1/8.57
= -0.29 hours
Negative values indicate that the waiting line system is unstable and solution is not feasible.
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mining company receives samples of ore every 5 minutes in a
Poissonian way, to which...
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Table: Average Number of Customer in Waiting
Line
Poisson Arrivals, Exponential Service Times
Number of Service Channels, M
rhoρ
1
2
3
4
5
0.1
0.0111
0.15
0.0264
0.0008
0.2
0.05
0.002
0.25
0.0833
0.0039
0.3
0.1285
0.0069
0.35
0.1884
0.011
0.4
0.2666
0.0166
0.45
0.3681
0.0239
0.0019
0.5
0.5
0.0333
0.003
0.55
0.6722
0.0449
0.0043
0.6
0.9
0.0593
0.0061
0.65
1.2071...
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Table: Average Number of Customer in Waiting
Line
Poisson Arrivals, Exponential Service Times
Number of Service Channels, M
rhoρ
1
2
3
4
5
0.1
0.0111
0.15
0.0264
0.0008
0.2
0.05
0.002
0.25
0.0833
0.0039
0.3
0.1285
0.0069
0.35
0.1884
0.011
0.4
0.2666
0.0166
0.45
0.3681
0.0239
0.0019
0.5
0.5
0.0333
0.003
0.55
0.6722
0.0449
0.0043
0.6
0.9
0.0593
0.0061
0.65
1.2071...
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difference between male and female sedation time (how long it takes
the animal to go down- in minutes). I know the data won’t be super
reliable being that there are more males than females. But I need
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