Question

A 32 ounce can of a popular fruit drink claims to contain 20% real fruit juice....

A 32 ounce can of a popular fruit drink claims to contain 20% real fruit juice. Since this is a 32 ounce can, they are actually claiming that the can contains 6.4 ounces of real fruit juice. The consumer protection agency samples 30 such cans of this fruit drink. The amount of real fruit juice in each can is given in the table below. Test the claim that the mean amount of real fruit juice in all 32 ounce cans is 6.4 ounces. Test this claim at the 0.01 significance level.DATA ( n =  30 )
Real Juice

ounces    
6.30
6.53
6.54
6.37
6.25
6.00
6.27
6.04
6.09
6.03
6.49
6.00
6.49
5.99
6.63
6.32
6.52
6.44
5.95
6.10
6.21
6.25
5.78
6.57
5.70
6.69
6.44
6.74
6.30
6.24


(b) What is the test statistic? Round your answer to 2 decimal places.
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(c) Use software to get the P-value of the test statistic. Round to 4 decimal places.
P-value =  
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Answer #1

The statistical software output for this problem is :

Test statistics = -2.56

P-value = 0.0160

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