Question

A group of 10 people is choosing a chairperson and vice-chairperson. They put all 10 people's...

A group of 10 people is choosing a chairperson and vice-chairperson. They put all 10 people's names into a hat. The first name drawn becomes chair. The second name drawn becomes vice-chair. How many possible combinations of chair and vice-chair are there?

A. 19

B. 90

C. 100

D. 10! (10 factorial)

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Answer #1

Note in this case order of name matters.

Hence, we use permutation for this sum.

Arrangement of chair and vice chair's all possible combinations are 10P2=10!/(10-2)!=10!/8!=10×9=90

Ans) 90

Option b is correct.

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