If you were in the laboratory, how would you prepare 1.00 L of a 0.50 M...

Question

Question

If you were in the laboratory, how would you prepare 1.00 L of a 0.50 M KCL solution?

science chemistry

Answer 1

Answer #1

Molarity=number of moles/volume in L

Number of moles=Molarity*volume in L

Number of moles=0.5M*1L

Number of moles=0.5 moles

Mass of KCl=number of moles*molar mass

Mass of KCl=0.5 moles*74.5513 g/mol =37.27565 g

Answer 2

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