In a survey sample of 830 correctional officers, the
mean number of hours worked per week is 39.04, with a standard
deviation of 11.51.
(A) Calculate the 99% confidence interval.
(B) interpret the results
(C) Let's say the sample had 50 cases. How would the results
change? Why?
In a survey sample of 830 correctional officers, the mean number of hours worked per week...
2. In estimating the mean number of television viewing hours per family per week, a random sample of 400 families yields a mean of 32.6 hours and a standard deviation of 9.9 hours (a) Find a 95% confidence interval for the average number of viewing hours per family per week in the population. Interpret. (b) Find a 99% confidence interval for the average number of viewing hours per family per week in the population. Interpret. (c) Suppose instead only 25...
4. A survey asked a random sample of 363 first-year students how many hours they studied during a particular week. The mean was 15.3 hours. Suppose we know that the population standard deviation is 8.5 hours. Construct a 90%, 95% and 99% confidence interval for the mean study time of all first year students at this university. Interpret the 90% confidence interval.
i cant get this one right. and its not 41.52 i tried that
too.
artial Question 6 172 pts In a survey sample of 83 respondents, the mean number of hours worked per week is 39.04, with a standard deviation of 11.51. Calculate a 95% confidence interval for these data. Lower bound: 36.53 Upper bound: 41.55 Answer 1: 36.53 Answer 2: 41.55
The mean number of hours of study time per week for a sample of 559 students is 23. If the margin of error for the population mean with a 99% confidence interval is 1.7, construct a 99% confidence interval for the mean number of hours of study time per week for all students
In a survey of 28 teenagers who were asked how many hours per week they spend watching T.V., the sample mean was 13 hours and the population standard deviation is 5.8 hours. Find a 99% Confidence Interval for the population mean number of hours teenagers watch T.V. Write the interval below. Write a sentence interpreting this. (Round answer to 2 decimal places)
The mean number of hours of part-time work per week for a sample of 526 college students is 28. if the margin of error for the population mean with a 99 % confidence interval is 2.2, construct a 99 % confidence interval for the mean number of hours of part-time work per week for all college students.
Question 4 1 pts A survey of 400 students provides a sample mean of 7.10 hours worked per week. From previous studies, the researcher knows that the standard deviation of this variable is 5 hours. What is a 95% confidence interval based on this sample? (6.10, 8.10) (6.45, 7.75) (6.61, 7.59) (7.10, 8.48)
In a survey conducted by a polling company, 1100 adult Americans were asked how many hours they worked in the previous week. Based on the results, a 95% confidence interval for the mean number of hours worked had a lower bound of 42.7 and an upper bound of 44.5. Provide two recommendations for decreasing the margin of error of the interval. Select all that apply. A. Increase the sample size. B. Decrease the standard deviation of hours worked. C. Use...
In a survey conducted by the Gallup Organization, 1100 adult Americans were asked how many hours they worked in the previous week. Based on the results, a 95% confidence interval for the mean number of hours worked had a lower bound of 42.7 and an upper bound of 44.5. Provide two recommendations for decreasing the margin of error of the interval. Select all that apply. A. Decrease the sample size. B. Increase the sample size. O C. Decrease the standard...
A survey of a simple random sample of 140 dieters revealed that the numbers of times they “cheated” on their diets had a mean of 7.0 times per week. Construct and interpret a 99% confidence interval for the mean number of times dieters “cheat” on their diets each week. Assume that the population standard deviation is 1.5 times per week.