Charge
Q=CV=180*120= 21600= 0.0216 microcolunb
Voltage applied to a 2 microferrad
V=Q/C= 3.10/2= 1.55 volt
Capacitance=
C=E*A/d, E= Er*E°= 2.1*8.854*10^-12
C= 2.1*8.854*10^-12 * 5/0.1*10^-3= 0.93 Microferrad
1) What charge is stored in a 180 µF180 µF capacitor when 120 V is applied...
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