Find the capacitance (in µF) of a parallel plate capacitor having plates of area 7.00 m2 that are separated by 0.300 mm of Teflon.
The concept of the capacitance for dielectric constant are used to solve this problem.
Use the parallel-plate capacitance for dielectric constant to calculate the capacitance of Teflon.
Write the expression of the parallel-plate capacitance for dielectric constant.

Here,
is the permittivity of free space,
is the dielectric constant,
is the area of the parallel plates and
is the distance between two plates.
Draw the diagram of the parallel-plate capacitor with dielectric material between the plates.
![Teflon
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+
+
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+
+
[
+
[ᎾᎾᎾᎾᎾ C]-
+
( ]
+
+
[ [
+)
+
+
+
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+
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+
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[](http://img.homeworklib.com/questions/234309c0-44f8-11ea-977e-3312d2d86999.png?x-oss-process=image/resize,w_560)
Understand that, the above figure shows the parallel-plate capacitor with dielectric Teflon among the plates.
Write the expression of the parallel-plate capacitance.

Substitute
for
,
for
,
for
and
for
.

The capacitance of a parallel plate is
.
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