Find the capacitance of a parallel plate capacitor having plates of area 5.75 m2 that are...

Question

Question

Find the capacitance of a parallel plate capacitor having plates of area 5.75 m2 that are separated by 0.495 mm of Teflon. Th

science physics

Answer 1

Answer #1

Capacitance (C) 2 k GoA = 2.1 x 8850x102, 5.75 0.495010? = 2.168107 F c=0.216UF

Answer 2

Similar Homework Help Questions

Find the capacitance of a parallel plate capacitor having plates of area 2.15 m2 that are...

Find the capacitance of a parallel plate capacitor having plates of area 2.15 m2 that are separated by 0.220 mm of Teflon. The dielectric constant of Teflon is 2.1.
Find the capacitance of a parallel plate capacitor having plates of area 2.95 m2 that are...

Find the capacitance of a parallel plate capacitor having plates of area 2.95 m2 that are separated by 0.280 mm of Teflon. The dielectric constant of Teflon is 2.1. ______ uF
Find the capacitance of a parallel plate capacitor having plates of area 4.00 m2 that are...

Find the capacitance of a parallel plate capacitor having plates of area 4.00 m2 that are separated by 0.100 mm of Teflon. µF

Find the capacitance of a parallel plate capacitor having plates of area 1.00 m2 that are...

Find the capacitance of a parallel plate capacitor having plates of area 1.00 m2 that are separated by 0.400 mm of Teflon. 1
Find the capacitance (in µF) of a parallel plate capacitor having plates of area 7.00 m2...

Find the capacitance (in µF) of a parallel plate capacitor having plates of area 7.00 m2 that are separated by 0.300 mm of Teflon.
(8%) Problem 8: Consider a parallel plate capacitor having plates of area 0.000475 m² that are...

(8%) Problem 8: Consider a parallel plate capacitor having plates of area 0.000475 m² that are separated by 0.095 mm of Teflon. The dielectric constant of Teflon is K= 2.1. Find the capacitance in F. Pot

1.Find the capacitance of a parallel plate capacitor having plates of area 5.00 m2 that are...

1.Find the capacitance of a parallel plate capacitor having plates of area 5.00 m2 that are separated by 0.200 mm of Teflon. 2.What capacitance is needed to store 3.00 µC of charge at a voltage of 120 V?
Consider a parallel plate capacitor having plates of area 0.00048 m^2 that are separated by 0.11...

Consider a parallel plate capacitor having plates of area 0.00048 m^2 that are separated by 0.11 mm of Teflon. The dielectric constant of Teflon x = 2.1
a) What is the capacitance of a parallel plate capacitor having plates of area 2.25 m2...

a) What is the capacitance of a parallel plate capacitor having plates of area 2.25 m2 that are separated by 0.0190 mm of neoprene rubber which has a dielectric constant of 6.7? uF b) What charge does it hold when 17.0 V is applied to it?

A parallel-plate capacitor, of area 6.62×10-2 m2, has the gap between the plates filled by Teflon,...

A parallel-plate capacitor, of area 6.62×10-2 m2, has the gap between the plates filled by Teflon, a dielectric. If a laboratory meter measures the capacitance to be 290 pF. What is the separation of the plates? Dielectric Constant κ at 20 °C Teflon 2.1 polyethylene 2.25 benzene 2.28 Mylar 3.1 Plexiglas 3.4 neoprene 6.7 glycerin 42.5 water 80.4