A parallel-plate capacitor, of area 6.62×10-2 m2, has the gap between the plates filled by Teflon, a dielectric. If a laboratory meter measures the capacitance to be 290 pF. What is the separation of the plates?
| Dielectric Constant κ at 20 °C | |
|---|---|
| Teflon | 2.1 |
| polyethylene | 2.25 |
| benzene | 2.28 |
| Mylar | 3.1 |
| Plexiglas | 3.4 |
| neoprene | 6.7 |
| glycerin | 42.5 |
| water | 80.4 |
A parallel-plate capacitor, of area 6.62×10-2 m2, has the gap between the plates filled by Teflon,...
A parallel-plate capacitor, of area 6.06×10-2 m2, has a gap between the plates filled by polyethylene, a dielectric. A laboratory meter measures the capacitance as 450 pF. What is the capacitance when there is only air in the gap? What is the separation of the plates?
Find the capacitance of a parallel plate capacitor having plates of area 5.75 m2 that are separated by 0.495 mm of Teflon. The dielectric constant of Teflon is 2.1 X How is capacitance related to plate area and separation for a parallel plate capacitor? Did you consider the effect of the dielectric? HF
a) What is the capacitance of a parallel plate capacitor having plates of area 2.25 m2 that are separated by 0.0190 mm of neoprene rubber which has a dielectric constant of 6.7? uF b) What charge does it hold when 17.0 V is applied to it?
A parallel-plate capacitor has plates of area 3.55×10−4 m2 A) What plate separation is required if the capacitance is to be 1490 pF ? Assume that the space between the plates is filled with air? (Dielectric constant for air is 1.00059) B) What plate separation is required if the capacitance is to be 1490 pF ? Assume that the space between the plates is filled with paper. (Dielectric constant for paper is 3.7)
Find the capacitance of a parallel plate capacitor having plates of area 2.15 m2 that are separated by 0.220 mm of Teflon. The dielectric constant of Teflon is 2.1.
An air-filled parallel-plate capacitor has a capacitance of 1.4 pF. The separation of the plates is doubled and wax is inserted between them. The new capacitance is 2.1 pF. Find the dielectric constant of the wax.
Find the capacitance of a parallel plate capacitor having plates of area 2.95 m2 that are separated by 0.280 mm of Teflon. The dielectric constant of Teflon is 2.1. ______ uF
A parallel-plate capacitor with plates of area 2.80 ✕ 10-4 m2 is being designed to have a capacitance of 1330 pF. (a) What plate separation is required if the space between the plates is filled with air? (b) What plate separation is required if the space between the plates is filled with mylar?
The figure shows a parallel-plate capacitor of plate area A and plate separation d. A potential differenceV0 is applied between the plates. While the
battery remains connected, a dielectric slab of thickness b and dielectric constant κ is placed between the plates
as shown. Assume A = 130 cm2, d = 1.94
cm, V0 = 72.6 V, b = 0.735 cm, and κ =
3.15. Calculate (a) the capacitance,(b) the charge on the capacitor plates,(c) the electric field in the gap, and(d)...
A parallel-plate capacitor has plates of area 2.88×10−4 m2 . Part A. What plate separation is required if the capacitance is to be 1660 pF ? Assume that the space between the plates is filled with air? (Dielectric constant for air is 1.00059) Express your answer using three significant figures.d= ? μm Part B What plate separation is required if the capacitance is to be 1660 pF ? Assume that the space between the plates is filled with paper. (Dielectric...