Two parallel-plate capacitors, 4.5 µF each, are connected in series to a 9.3 V battery. One of the capacitors is then squeezed so that its plate separation is halved. Because of the squeezing, (a) how much additional charge is transferred to the capacitors by the battery and (b) what is the increase in the sum of the charges: the charge on the positive plate of one capacitor plus the charge on the positive plate of the other capacitor? Give your answers in Coulombs.
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Two parallel-plate capacitors, 4.5 µF each, are connected in series to a 9.3 V battery. One...
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