What is the mass (in grams) of a CO_2 gas sample that occupies 5.66 L at STP?
At STP , volume of 1 mole of gas = 22.4 L
Hence, we can write , 22.4 L of CO 2 gas
1 mol of CO 2 gas
5.66 L of CO 2 gas
( 1
5.66 / 22.4 ) mol of CO 2 gas
5.66 L of CO 2 gas
0.2527 mol of CO 2 gas
We have, no. of moles = Mass / Molar mass
Mass of CO 2 gas = No. of moles of CO 2 gas
Molar mass of CO 2 gas
Mass of CO 2 gas = 0.2527 mol
44.01 g / mol = 11.12 g
ANSWER : 11.12 g of CO 2 gas occupies 5.66 L at STP.
What is the mass (in grams) of a CO_2 gas sample that occupies 5.66 L at...
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