Question

I neerd help with this Scilab program yo calculate the derivatives of this function between 0 and 2pi with step size 0,1;

y=sin(e^1.3cos(x))+1

Have to use mprintf(), modulo() and loop to out put in this format

xdata ydata xdata ydata

__________________________________

0.00000 0.00000   0,10000 0.41431

0.20000 0.83788 0.30000 1.26231

0.40000 1.65227 0.500000 1.95030

0.60000 2.09565 0.700000 2.04914

and so on, this is just how partially the program should look like

Answer 1

x=0:.1:2*%pi;
for i=1:length(x)
    mprintf('%10.5f %10.5f ',x(i),-1.3*sin(x(i))*exp(1.3*cos(x(i)))*cos(exp(1.3*cos(x(i)))))
    if modulo(i,2)==0
        mprintf('\n')
    end
    
end