Titration of Acetic Acid in Vinegar with NaOH Balanced Chemical Equation: NaOH + HC2H3O2 à H2O...
Titration of Acetic Acid in Vinegar with NaOH
Balanced Chemical Equation:
NaOH + HC2H3O2 à H2O + NaC2H3O2
Volume of HC2H3O2 used in the Erlenmeyer flask = 2.50 mL
Molarity (M) of NaOH (stated on label) = 0.150 M
|
NaOH Data |
Trial 1 |
Trial 2 |
Trial 3 |
|
Initial Volume (mL) |
0.00 |
16.10 |
31.70 |
|
Final Volume (mL) |
16.10 |
31.70 |
47.35 |
|
Total Volume (mL) |
16.10 |
15.60 |
15.65 |
|
Average volume (mL) |
|||
|
Average volume (L) |
|||
First, Calculate the Average volume of NaOH in Liters
Homework Answers
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Titration of Acetic Acid in Vinegar with NaOH
Balanced Chemical Equation:
NaOH + HC2H3O2 à H2O...
Acid-Base Titration % A. Concentration of Acetic Acid in Vinegar nei ica's 1. Brand clice Volume...
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Exp 9 titration of vinegar procedure b molarity of NaOH = .0859 ROCEDURE B. DETERMINATION OF...
Exp 9 titration of vinegar procedure b
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ROCEDURE B. DETERMINATION OF CONCENTRATION OF ACETIC ACID IN UNKNOWN SAMPLES Titration of vinegar solutions Trial 1 Trial 2 Trial 3 1. Volume of vinegar solution being titrated in milliliters (mL) 25.00 mL 25.00 mL 25.00 ml 2. Volume of vinegar solution being titrated in Liters (L) 0.0250 L 0.0250 L 0.0250 L 3. Final buret reading in ml 16. 20m 16.316L 16.25ml 4. Initial buret reading in...
Section Acid-Base Titration Team LAB 10 Results A. Concentration of Acetic Acid in Vinegar 1. Brand:...
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B. Analysis of Vinegar (Acetie Acid) Trial aceti ic aci S Advertised % Acetic Acid Trial...
B. Analysis of Vinegar (Acetie Acid) Trial aceti ic aci S Advertised % Acetic Acid Trial #2 Trial #3 NAT of vi 8. Volume of vinegar 10 ml 10ml 1.0 ml 9. Final buret reading 6.4 _ml 10. Initial buret reading 0.00 mL 6.4 ml. 13.4_mL 6.4 ml 7.0 ml 20.2__ml 13.4 ml 6.8 mi 11. Volume of NaOH 12. Molarity of vinegar (Show set-up) - M - 13. Average molarity of vinegar 14. Percent acetic acid in vinegar (Show...
5. Determine the average value for the molarity of the acetic acid in vinegar. Show your...
5. Determine the average value for the molarity of the acetic acid in vinegar. Show your calculation 6. Determine the deviation between each individual molarity for acetic acid and the average value from question 4, above. Notice that the formula below uses absolute values: you only care about how big the difference is not whether cach trial value was higher or lower than the average. Deviation = (individual trial value)-(average value from #5) Trial Ideviation Trial 2 deviation Trial 3...
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Trial one Trial two Trial three Volume of oxalic acid (mL) 10.1 mL 10.2 mL 10.1 mL Moles of oxalic acid (moles) 0.0026 0.0026 0.0026 Initial volume of NaOH (mL) 18.7 mL 26.5 mL 34.6 mL Final volume of NaOH (mL) 26.5 mL 34.6 mL 42.6 mL Delivered volume of NaOH (moles) 7.8 mL 8.1 mL 8 mL Moles of NaOH (moles) 0.0052 0.0052 0.0052 Molarity of NaOH (M) 0.6667 0.6420 0.65 Average Molarity NaOH (M) 0.65 Concentration oxalic acid...
A titration of vinegar with a solution of NaOH was performed. If 3.35 mL of vinegar...
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H2O NaCl Balance the equation for the reaction that occurs in this titration: HCI + NaOH - ROUGH TITRATION (with 1 mL increments to reach approximate end point) Rough Titration data 0.00 m Initial volume of NAOH (mL); read the buret Final volume of NaOH (m L); read the buret Volume of NAOH used (mL); subtract 13.00 mL 13 00 mL PRECISE TITRATIONS (with drop-by-drop increments to reach precise endpoint) Trial 3 Trial 2 Trial 1 data data data 13.00...
(TITRATION) What would be the calculations based on the trial data gathered? I obtained 50mL of...
(TITRATION) What would be the calculations based on the trial
data gathered?
I obtained 50mL of NaOH solution and then pipetted 5.0mL of
pickle juice into an Erlenmeyer flask. I then added 50mL of
distilled water and 2 drops of indicator.
Molarity of NaOH: 0.1001M Trial 1 Vinitial: 24.50 mL Vfinal: 45.72 mL Trial 2 Vinitial: 2.42 mL Vfinal: 23.74 mL Trial 3 Vinitial: 23.74 mL Vfinal: 44.22 mL Calculations Assume that the acid present in your food sample is...
Lab Report: Titration of Vinegar Experimental Data Trial 1 Trial 2 Initial Buret Reading Trial 3...
Lab Report: Titration of Vinegar Experimental Data Trial 1 Trial 2 Initial Buret Reading Trial 3 OML OML OML Final Buret Reading 40 6 ML 40-3 ML 41-7 ML Volume of NaOH used 40.0ML 4 7 40.3 ML Molarity of NaOH used Volume of vinegar used 5ML SML 5ML Data Analysis 1. Write the balanced equation for the neutralization reaction between aqueous sodium hydroxide and acetic acid. The Molarity of Acetic Acid in Vinegar Trial 1 Trial 2 Trial 3...
Acid-Base Titration % A. Concentration of Acetic Acid in Vinegar nei ica's 1. Brand clice Volume 5.0 mL (% on label) 2. Molarity (M) of NaOH Oil M M Trial 1 Trial 2 Trial 3 3. Initial NaOH level in buret 1.8 500 4. Final NaOH level in buret 148.3 5. Volume (mL) of NaOH used 6. Average volume (mL) 7. Average volume in liters (L) mole NaOH 8. Moles of NaOH used in titration (Show calculations.) 9. Moles of...
Exp 9 titration of vinegar procedure b
molarity of NaOH = .0859
ROCEDURE B. DETERMINATION OF CONCENTRATION OF ACETIC ACID IN UNKNOWN SAMPLES Titration of vinegar solutions Trial 1 Trial 2 Trial 3 1. Volume of vinegar solution being titrated in milliliters (mL) 25.00 mL 25.00 mL 25.00 ml 2. Volume of vinegar solution being titrated in Liters (L) 0.0250 L 0.0250 L 0.0250 L 3. Final buret reading in ml 16. 20m 16.316L 16.25ml 4. Initial buret reading in...
Section Acid-Base Titration Team LAB 10 Results A. Concentration of Acetic Acid in Vinegar 1. Brand: Great Value Volume: 5.0mL. (% on label) 5% 2. Molarity (M) of NaOHO.099M Trial 3 Trial 1 Trial 2 1.4 mL 0.7 mL 1.2 ml 3. Initial NaOH level in buret 41.5mL 41.3 mL 41.5ml 4. Final NaOH level in buret 5. Volume (ml) of NaOH used 6. Average volume (ml) 7. Average volume in liters (L) 8. Moles of NaOH used in titration...
B. Analysis of Vinegar (Acetie Acid) Trial aceti ic aci S Advertised % Acetic Acid Trial #2 Trial #3 NAT of vi 8. Volume of vinegar 10 ml 10ml 1.0 ml 9. Final buret reading 6.4 _ml 10. Initial buret reading 0.00 mL 6.4 ml. 13.4_mL 6.4 ml 7.0 ml 20.2__ml 13.4 ml 6.8 mi 11. Volume of NaOH 12. Molarity of vinegar (Show set-up) - M - 13. Average molarity of vinegar 14. Percent acetic acid in vinegar (Show...
5. Determine the average value for the molarity of the acetic acid in vinegar. Show your calculation 6. Determine the deviation between each individual molarity for acetic acid and the average value from question 4, above. Notice that the formula below uses absolute values: you only care about how big the difference is not whether cach trial value was higher or lower than the average. Deviation = (individual trial value)-(average value from #5) Trial Ideviation Trial 2 deviation Trial 3...
H2O NaCl Balance the equation for the reaction that occurs in this titration: HCI + NaOH - ROUGH TITRATION (with 1 mL increments to reach approximate end point) Rough Titration data 0.00 m Initial volume of NAOH (mL); read the buret Final volume of NaOH (m L); read the buret Volume of NAOH used (mL); subtract 13.00 mL 13 00 mL PRECISE TITRATIONS (with drop-by-drop increments to reach precise endpoint) Trial 3 Trial 2 Trial 1 data data data 13.00...
(TITRATION) What would be the calculations based on the trial
data gathered?
I obtained 50mL of NaOH solution and then pipetted 5.0mL of
pickle juice into an Erlenmeyer flask. I then added 50mL of
distilled water and 2 drops of indicator.
Molarity of NaOH: 0.1001M Trial 1 Vinitial: 24.50 mL Vfinal: 45.72 mL Trial 2 Vinitial: 2.42 mL Vfinal: 23.74 mL Trial 3 Vinitial: 23.74 mL Vfinal: 44.22 mL Calculations Assume that the acid present in your food sample is...
Lab Report: Titration of Vinegar Experimental Data Trial 1 Trial 2 Initial Buret Reading Trial 3 OML OML OML Final Buret Reading 40 6 ML 40-3 ML 41-7 ML Volume of NaOH used 40.0ML 4 7 40.3 ML Molarity of NaOH used Volume of vinegar used 5ML SML 5ML Data Analysis 1. Write the balanced equation for the neutralization reaction between aqueous sodium hydroxide and acetic acid. The Molarity of Acetic Acid in Vinegar Trial 1 Trial 2 Trial 3...
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