A sample of 85 peoples daily workout times was found to have a sample mean of...
A random sample of 50 students is selected and it is found that the mean of daily internet usage is 70.8 minutes with standard deviation of 13.8 minutes. A hypothesis test was performed to determine whether the true mean usage, µ equal to 72.0 minutes or not. What is the p-value of the test?
Use the same sample of 51 boys in problem. The standard deviation of daily iron intake in the larger population of 9 to 11-year-old boys was 5.56mg. a. We wish to test if the standard deviation from the low-income group is lower than that of the general population. Use -0.10. : H: ii. Summary Sample Statistics: iii. Significance level: iv. p-value: v. Conclusion: vi. Is the standard deviation of iron intake among the low-income group lower than that of the...
A survey of a random sample of 1000 smartphone owners found that the mean daily time spent communicating on a smart phone was 131.4 minutes if we assume the population standard deviation is 21.2 minutes the 95% confidence interval for the population mean will be 130.1<u<132. 7minutes. what is the meaning of these results
The inter-arrival times of customers arriving at a HDB coffee shop were found to follow Exponential distribution L H Frequency The grouped data shows frequency counts of sampled inter- 0 1 41 arrival times occurring greater than or equal to L minutes and 1 2 21 less than H minutes. A total of 100 sample inter-arrival times 23 19 were measured. Use the mid-point as a representative data in calculations for each interval. Test the claim that the population mean...
QUESTION: The mean weight of watermelons found in a garden last year was 15.4 kg. In a sample of 35 watermelons at the same time this year in the same colony, the mean watermelon weight was found to be 14.6 kg. Assume the population standard deviation is 2.5 kg. (i) At 5% significance level, can we reject the null hypothesis that the mean watermelon weight does not differ from last year? (ii) What is the test statistics? (iii) What is...
The population mean of ages for all females on the Titanic (survivors and non-survivors) was 24 years. Is the sample data you were given for the female ages greater than the population ages? Use a .05 level of significance. Here is the data of sample ages :47, 29, 19, 22, 24, 9, 22, 16, 40, 45, 1, 50, 4 What test are you going to run? One mean t-test, Regression, One mean z-test, ANOVA correct null hypothesis (Ho): correct alternative...
A simple random sample of size n=40 is drawn from a population. The sample mean is found to be 106.9,and the sample standard deviation is found to be 15.1. Is the population mean greater than 100 at the α=0.025 level of significance? A) Determine the null and alternative hypotheses. B) Compute the test statistic C) Determine the P-value. (Round to three decimal places as needed.) D) What is the result of the hypothesis test? ____ the null hypothesis because the...
"Find the p-value of a test of hypothesis if the value found for the sample mean was 591.33 the Null Hypothesis assumes that the population mean is Mu = 538, the population standard deviation is 152 and the sample size is 13" The correct answer isn't 0.204 or 0.2058
A population is sampled 79 times yielding sample mean x = 25.2 and sample standard deviation s = 7.4. A similar population has mean Mo = 27. You will run a one-tailed hypothesis test against H : u= 27 with a = 0.05. The Z-score of sampled data is: Zz = The a cutoff value is: za = (Choose Zą so that it has the same sign as zz) In this case, are we rejecting the null hypothesis? Result: select...
A study of 55 American adults was taken and found that the mean number of times they went to the movies in the past 6 months was 9.46 with standard deviation 1.8. This study was to performed to determine if this value has changed since 2000 when the mean was 10 every 6 months. Step 1 of 5: What type of hypothesis test should be performed here? Step 2 of 5: State the null hypothesis. Step 3 of 5: State...