2 kg of water at room temperature (25◦C) is poured into a .1 kg glass jar also at room temperature (25◦C). .15 kg of ice cubes at −10◦C are added to the the water. Assume that the system is isolated
(a) What is the temperature of the system when it reaches thermal equilibrium?
(b) Describe in detail the contents of the jar once equilibrium is reached.
Water -Specific heat = 4190 , Ice - Specific heat = 2090 , Glass jar - Specific heat = 840 , Lf = 3.33 x 10^5
2 kg of water at room temperature (25◦C) is poured into a .1 kg glass jar...
200 g of water at room temperature is poured into a 100 g glass jar also at room temperature. 150 g of ice cubes at −10◦C are added to the the water. (a) What is the temperature of the system when it reaches thermal equilibrium? (b) Describe in detail the contents of the jar once equilibrium is reached. Assume that the system is isolated and room temperature is 25◦C.
200 g of water at room temperature is poured into a 100 g glass jar also at room temperature. 150 g of ice cubes at −10◦C are added to the the water. (a) What is the temperature of the system when it reaches thermal equilibrium? (b) Describe in detail the contents of the jar once equilibrium is reached. **Assume that the system is isolated and room temperature is 25◦C.
Bob orders a cup of hot coffee (0.22 kg) at a café. Finding the coffee to be too hot (56°C), he decides to put ice cubes with a total mass of 21 g into the cup. The ice is at an initial temperature of -5°C. Heat of fusion of water: 3.33 x 105 J/kg Specific heat of ice: 2090 J/(kg · K) Specific heat of water: 4190 J/(kg · K). a) What is the total energy needed to warm the...
A 0.0575 kg ice cube at −30.0°C is placed in 0.617 kg of 35.0°C water in a very well insulated container, like the kind we used in class. The heat of fusion of water is 3.33 x 105 J/kg, the specific heat of ice is 2090 J/(kg · K), and the specific heat of water is 4190 J/(kg · K). The system comes to equilibrium after all of the ice has melted. What is the final temperature of the system?
A 0.0725 kg ice cube at −30.0°C is placed in 0.497 kg of 35.0°C water in a very well insulated container, like the kind we used in class. The heat of fusion of water is 3.33 x 105 J/kg, the specific heat of ice is 2090 J/(kg · K), and the specific heat of water is 4190 J/(kg · K). The system comes to equilibrium after all of the ice has melted. What is the final temperature of the system?
Ouestions 19-20. 1 kg of water at 80 °C is poured into a 1 kg glass cup initially at 20 °C The specific heat of glass is cglass- 840Assume cwater 9 Cglass. kg.°C 19. What will be the equilibrium temperature? (a) 32 °C (b) 45 °C (c) 68 °C (d) 74 °C 20. How much heat will the cup receive in the process? (a) 45,360 J (b) 57,290 J (c) 63,120 J (d) 77,410.J
A beaker with negligible mass contains 0.50 kg of water at a temperature of 80 °C. How many grams of ice at a temperature of -20 °C must be dropped in the water so that the final temperature of of the system is 30 °C? (Cice = 2100 J/ (kg °C) ), Cwater = 4190 J/ (kg °C) ), LF = 3.33 x 105 J/kg Could you also show how LF is used?
A jar of tea is placed in sunlight until it reaches an equilibrium temperature of 30◦C . In an attempt to cool the liquid, which has a mass of 165 g , 136 g of ice at 0.0 ◦C is added. At the time at which the temperature of the tea is 23.5 ◦C , find the mass of the remaining ice in the jar. The specific heat of water is 4186 J/kg · ◦ C . Assume the specific...
Suppose 0.385 kg of water initially at 39.5°C is poured into a 0.300 kg glass beaker having a temperature of 25.0°C. A 0.500 kg block of aluminum at 37.0°C is placed in the water, and the system insulated. Calculate the final equilibrium temperature of the system. °C
A jar of tea is placed in sunlight until it reaches an equilibrium temperature of 32.6 ◦C . In an attempt to cool the liquid, which has a mass of 189 g , 98.8 g of ice at 0.0 ◦C is added. At the time at which the temperature of the tea is 28.6 ◦C , find the mass of the remaining ice in the jar. The specific heat of water is 4186 J/kg · ◦ C . Assume the...