A positive charge of 5.00 μC is fixed in place. From a distance of 4.60 cm a from the fixed positive charge, a particle of mass 6.40 g and charge +3.60 μC is released from rest. What is the speed of the +3.60 μC when it is 9.00 cm away from the fixed positive charge?
using conservation of energy
electric potential energy = kinetic energy
k q1 q2 * ( 1/ r1 - 1/r2) = 0.5 m v^2
9* 10^9* 5* 3.6* 10^-12* ( 1/ 0.046 - 1/ 0.09) = 0.5* 6.4* 10^-3 v^2
v = 23.196 m/s
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