Question

def list_to_dict(lst: list) -> dict:
    '''
    Given a list L that may have sublists nested within it at an arbitrary
    depth, return a dictionary that has all the values from the list as its
    values, and the associated keys for each value are the indices that
    we would need to go through to get to that value. The key is represented
    as a string as exemplified below.
    
    e.g. In the list shown below, the value 'a' is at L[0] so
    the key for this value in the dictionary returned is just '0'.
    The value 'd' is at index L[2][1] so the key for this value is
    '2->1'. The value 'e' is at index L[2][2][0], so the key for this
    value is '2->2->0' and so on.

    Note: Your code MUST be recursive

    >> L = ['a', 'b', ['c', 'd', ['e']]]
    >> list_to_dict(L)
    {'0': 'a', '1': 'b', '2->0': 'c', '2->1': 'd', '2->2->0': 'e'}
    '''

    # YOUR CODE HERE
    pass

Answer 1

`Hey,

Note: Brother in case of any queries, just comment in box I would be very happy to assist all your queries

Note: Brother sometimes while uploading on HomeworkLib the indentations change. So, I request you to verify it with screenshot once.

Please find the python function to print the dictionary with list elements and its index.

Note: Sometimes printing the dictionary will not display the values based on the position it is stored. But it will have all the elements stored in it from the given list and position will be different.

It is one of the property of dictionary.

Program:

L = ['a', 'b', ['c', 'd', ['e']]]

def list_to_dict(L):
"""This function takes list as argument and returns the
dictionary which shows list elements index"""
dict1={}
for i in range(len(L)):
if type(L[i]) != list:
dict1[str(i)]=L[i]
else:
#if the element is not list then call the same function again to
#populate the dictionary
temp=list_to_dict(L[i])
key=str(i)+"->"
key_temp=key
for k in temp:
dict1[key+str(k)]=temp[k]
  
  
#return the dictionary
return dict1
  
  
print(list_to_dict(L))

Output:

{'0': 'a', '2->1': 'd', '1': 'b', '2->0': 'c', '2->2->0': 'e'}

Screen Shot:

Kindly revert for any queries

Thanks.