A teacher measured study hours of last week from a sample of students in her class...
A teacher measured study hours of last week from a sample of students in her class Here are data from the sample. The mean is 50 and the standard deviation is 6. You can round to 2 decimal places for z-scores.
What is the percentile of Jones when his raw score is 56?
Homework Answers
=1
P[Z<1]= 0.8413
| Therefore, 0.8413 or 84.13% of Jones when his raw score is 56 |
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