Question

Part C

Now, repeat the experiment several times to investigate how the amount of time to charge the capacitor (resulting in a voltage difference equal to the emf of the battery) depends on the capacitance of the capacitor and the resistance of the resistor. Each time you repeat the experiment, you first need to open the switch and right-click or control-click on the capacitor to select Discharge Capacitor.

The amount of time ________ if the resistance is increased and ________ if the capacitance is increased.

A) decreases / decreases

B) increases / decreases

C) decreases / increases

D) increases / increases

For more detail check this question

https://www.chegg.com/homework-help/questions-and-answers/learning-goal-understand-time-dependent-behavior-current-circuits-containing-batteries-cap-q40363122?trackid=NV0FdHE2

i need help for part d as well so i will post part d in comments you have to give answer for that part

Answer 1

Charging of a capacitor through a resistance R is given by-

Where RC is called time constant of the circuit.Charging time of capacitor depends upon time constant .If time constant of circuit is large then capacitor takes more time to charge and vice-versa.A capacitor can be considered to be fully charged after 5 time constants.

So if we increase the value of R then obviously time constant also increases so the amount of time to charge the capacitor also increases.

And If we increase the value of C then again time constant increases so again the amount of time required to charge the capacitor increases.

So fill in the blank will be like this-

The amount of time increases if the resistance increased and also increases if the capacitance is increased.