Assuming a population is in Hardy-Weinberg equilibrium and the frequency of the recessive allele (q) is equal to 0.2 (20%), you could estimate that the frequency of Homozygous Recessive individuals in this population would be _______________________
q = 0.2
q^2 = 0.2 × 0.2 = 0.04
p (frequency of dominant allele) + q (frequency of recessive allele) = 1
p^2 (dominant genotype) + 2pq (heterozygous) + q^2 (recessive genotype) = 1
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Assuming a population is in Hardy-Weinberg equilibrium and the frequency of the recessive allele (q) is...
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Evolution
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The basic equations of Hardy-Weinberg Equilibrium p² + 2pq + q2 = 1 p+q=1 p= frequency of the dominant allele in the population 9 = frequency of the recessive allele in the population př= percentage of homozygous dominant individuals q* = percentage of homozygous recessive individuals 2pq - percentage of heterozygous individuals 1. You have sampled a population in which you know that the percentage of the homozygous recessive genotype...