IP Address: 192.169.69.47
Subnet Mask: 255.255.192.0
find Network address, Broadcast address, first valid host address, last valid host address and number of valid hosts in the network.
show very clear steps for all the calculations.
IP Address: 192.169.69.47
----------------------------------------
Let's first convert this into binary format
192.169.69.47
Let's convert all octets to binary separately
Converting 192 to binary
Divide 192 successively by 2 until the quotient is 0
> 192/2 = 96, remainder is 0
> 96/2 = 48, remainder is 0
> 48/2 = 24, remainder is 0
> 24/2 = 12, remainder is 0
> 12/2 = 6, remainder is 0
> 6/2 = 3, remainder is 0
> 3/2 = 1, remainder is 1
> 1/2 = 0, remainder is 1
Read remainders from the bottom to top as 11000000
So, 192 of decimal is 11000000 in binary
192 in binary is 11000000
Converting 169 to binary
Divide 169 successively by 2 until the quotient is 0
> 169/2 = 84, remainder is 1
> 84/2 = 42, remainder is 0
> 42/2 = 21, remainder is 0
> 21/2 = 10, remainder is 1
> 10/2 = 5, remainder is 0
> 5/2 = 2, remainder is 1
> 2/2 = 1, remainder is 0
> 1/2 = 0, remainder is 1
Read remainders from the bottom to top as 10101001
So, 169 of decimal is 10101001 in binary
169 in binary is 10101001
Converting 69 to binary
Divide 69 successively by 2 until the quotient is 0
> 69/2 = 34, remainder is 1
> 34/2 = 17, remainder is 0
> 17/2 = 8, remainder is 1
> 8/2 = 4, remainder is 0
> 4/2 = 2, remainder is 0
> 2/2 = 1, remainder is 0
> 1/2 = 0, remainder is 1
Read remainders from the bottom to top as 1000101
So, 69 of decimal is 1000101 in binary
69 in binary is 01000101
Converting 47 to binary
Divide 47 successively by 2 until the quotient is 0
> 47/2 = 23, remainder is 1
> 23/2 = 11, remainder is 1
> 11/2 = 5, remainder is 1
> 5/2 = 2, remainder is 1
> 2/2 = 1, remainder is 0
> 1/2 = 0, remainder is 1
Read remainders from the bottom to top as 101111
So, 47 of decimal is 101111 in binary
47 in binary is 00101111
====================================================================================
|| 192.169.69.47 in binary notation is
11000000.10101001.01000101.00101111 ||
====================================================================================
Subnet address: 255.255.192.0
----------------------------------------
Let's convert this into binary format
255.255.192.0
Let's convert all octets to binary separately
Converting 255 to binary
Divide 255 successively by 2 until the quotient is 0
> 255/2 = 127, remainder is 1
> 127/2 = 63, remainder is 1
> 63/2 = 31, remainder is 1
> 31/2 = 15, remainder is 1
> 15/2 = 7, remainder is 1
> 7/2 = 3, remainder is 1
> 3/2 = 1, remainder is 1
> 1/2 = 0, remainder is 1
Read remainders from the bottom to top as 11111111
So, 255 of decimal is 11111111 in binary
255 in binary is 11111111
Converting 255 to binary
Divide 255 successively by 2 until the quotient is 0
> 255/2 = 127, remainder is 1
> 127/2 = 63, remainder is 1
> 63/2 = 31, remainder is 1
> 31/2 = 15, remainder is 1
> 15/2 = 7, remainder is 1
> 7/2 = 3, remainder is 1
> 3/2 = 1, remainder is 1
> 1/2 = 0, remainder is 1
Read remainders from the bottom to top as 11111111
So, 255 of decimal is 11111111 in binary
255 in binary is 11111111
Converting 192 to binary
Divide 192 successively by 2 until the quotient is 0
> 192/2 = 96, remainder is 0
> 96/2 = 48, remainder is 0
> 48/2 = 24, remainder is 0
> 24/2 = 12, remainder is 0
> 12/2 = 6, remainder is 0
> 6/2 = 3, remainder is 0
> 3/2 = 1, remainder is 1
> 1/2 = 0, remainder is 1
Read remainders from the bottom to top as 11000000
So, 192 of decimal is 11000000 in binary
192 in binary is 11000000
Converting 0 to binary
Divide 0 successively by 2 until the quotient is 0
Read remainders from the bottom to top as
So, 0 of decimal is in binary
0 in binary is 00000000
====================================================================================
|| 255.255.192.0 in binary notation is
11111111.11111111.11000000.00000000 ||
====================================================================================
Remove all dots to form
11111111111111111100000000000000
Remove all 0's from the right side to form 111111111111111111
Number of 1's in this is 18
so, Subnet mask is /18
For Calculating network ID, keep first 18 bits of
11000000.10101001.01000101.00101111 and set all remaining bits to
0.
so, network ID in binary is
11000000.10101001.01000000.00000000
11000000.10101001.01000000.00000000:
----------------------------------------
11000000.10101001.01000000.00000000
Let's convert all octets to decimal separately
Converting 11000000 to decimal
=> 11000000
=> 1x2^7+1x2^6+0x2^5+0x2^4+0x2^3+0x2^2+0x2^1+0x2^0
=> 1x128+1x64+0x32+0x16+0x8+0x4+0x2+0x1
=> 128+64+0+0+0+0+0+0
=> 192
11000000 in decimal is 192
Converting 10101001 to decimal
=> 10101001
=> 1x2^7+0x2^6+1x2^5+0x2^4+1x2^3+0x2^2+0x2^1+1x2^0
=> 1x128+0x64+1x32+0x16+1x8+0x4+0x2+1x1
=> 128+0+32+0+8+0+0+1
=> 169
10101001 in decimal is 169
Converting 01000000 to decimal
=> 01000000
=> 0x2^7+1x2^6+0x2^5+0x2^4+0x2^3+0x2^2+0x2^1+0x2^0
=> 0x128+1x64+0x32+0x16+0x8+0x4+0x2+0x1
=> 0+64+0+0+0+0+0+0
=> 64
01000000 in decimal is 64
Converting 00000000 to decimal
=> 00000000
=> 0x2^7+0x2^6+0x2^5+0x2^4+0x2^3+0x2^2+0x2^1+0x2^0
=> 0x128+0x64+0x32+0x16+0x8+0x4+0x2+0x1
=> 0+0+0+0+0+0+0+0
=> 0
00000000 in decimal is 0
====================================================================================
|| 11000000.10101001.01000000.00000000 in decimal notation is
192.169.64.0 ||
====================================================================================
===========================================
|| So, Network ID is 192.169.64.0 ||
===========================================
For Calculating broadcast ID, keep first 18 bits of
11000000.10101001.01000101.00101111 and set all remaining bits to
1.
so, broadcast ID in binary is
11000000.10101001.01111111.11111111
11000000.10101001.01111111.11111111:
----------------------------------------
11000000.10101001.01111111.11111111
Let's convert all octets to decimal separately
Converting 11000000 to decimal
=> 11000000
=> 1x2^7+1x2^6+0x2^5+0x2^4+0x2^3+0x2^2+0x2^1+0x2^0
=> 1x128+1x64+0x32+0x16+0x8+0x4+0x2+0x1
=> 128+64+0+0+0+0+0+0
=> 192
11000000 in decimal is 192
Converting 10101001 to decimal
=> 10101001
=> 1x2^7+0x2^6+1x2^5+0x2^4+1x2^3+0x2^2+0x2^1+1x2^0
=> 1x128+0x64+1x32+0x16+1x8+0x4+0x2+1x1
=> 128+0+32+0+8+0+0+1
=> 169
10101001 in decimal is 169
Converting 01111111 to decimal
=> 01111111
=> 0x2^7+1x2^6+1x2^5+1x2^4+1x2^3+1x2^2+1x2^1+1x2^0
=> 0x128+1x64+1x32+1x16+1x8+1x4+1x2+1x1
=> 0+64+32+16+8+4+2+1
=> 127
01111111 in decimal is 127
Converting 11111111 to decimal
=> 11111111
=> 1x2^7+1x2^6+1x2^5+1x2^4+1x2^3+1x2^2+1x2^1+1x2^0
=> 1x128+1x64+1x32+1x16+1x8+1x4+1x2+1x1
=> 128+64+32+16+8+4+2+1
=> 255
11111111 in decimal is 255
=======================================================================================
|| 11000000.10101001.01111111.11111111 in decimal notation is
192.169.127.255 ||
=======================================================================================
================================================
|| So, broadcast ID is 192.169.127.255 ||
================================================
For Calculating first valid address in subnet, add 1 to
the network address.
Network Address is 192.169.64.0
==============================================================
|| So, first valid address in subnet is 192.169.64.1 ||
==============================================================
For Calculating last valid address in subnet, remove 1
from the broadcast address.
Broadcast Address is 192.169.127.255
================================================================
|| So, last valid address in subnet is 192.169.127.254 ||
================================================================
Number of valid hosts in the network
> 2^(32 - number of 1's in subnet) - 2
> 2^(32 - 18) - 2
> 2^(14) - 2
> 16384 - 2
> 16382
=============================================================
|| So, number of valid hosts in the subnet is 16382 ||
=============================================================
IP Address: 192.169.69.47 Subnet Mask: 255.255.192.0 find Network address, Broadcast address, first valid host address, last...
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using the information given below
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** corrections
# of bits in subnet for A
:6
# of bits in submet for B:
3
PC-A
R1 G0/0
R GO/1
S1
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