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A 220-W, 2 pole, 155-V 60-Hz single phase induction motor delivers rated output at a slip...
Problem Solving: 1. A 220V, 4-pole, 60Hz, 1-phase induction motor has an effective rotor resistance and leakage reactance of 0.5 Ohms and 5 ohms respectively. It is running at a speed of 1,800 rpm. Determine: a. Frequencies of forward and backward rotor current components b. Relative magnitudes of forward and backward fluxes. Neglect magnetizing current and stator impedance. A 220-W, 2-pole, 115-V, 60-Hz single-phase induction motor delivers rated output at a slip 10%. The total copper loss at full load...
2. A 208V, two pole, 60 Hz, y connected wound rotor induction motor is rated at 15hp. Its equivalent circuit parameters are R:-0.200, R:-0.120, X.-X-0.410, X-150. The rotational losses are 430W. The motor drives a mechanical load with a slip of 5 percent. By using simplified equivalent circuit calculate; (30 pts) a) The motor speed in revolutions per minute and radians per second. b) The line current c) The stator copper losses. d) The air gap power. e) The power...
. A 460-V 460-V, 25-hp, 60-Hz, six-pole, Y-connected induction motor has the following impedanc ohms per phase referred to the stator circuit. Ri= 0.212 R2 = 0.282 X1 = 1.055 12 X2 = 1.055 22 XM = 33.9 W The total rotational losses are 1100 W and are assumed to be constant. The core loss is lumped with the rotational losses. For a rotor slip of 4% at the rated voltage and rated frequency, a) The input power b) Peony...
A 25-hp, 208-V, 60-Hz, two-pole, Y-connected induction motor operates at slip of 5% at rated conditions. The motor parameters are given in ohms per phase as follows: ??=0.3 ??=0.4 ??=0.1 ??=0.4 ??=25.0 Assume core loss of 150 W and rotational loss of 225 W, Find Stator Current, Electromechanical torque, Power out, Efficiency, Power Factor and PowerFlow Diagram. Use the exact model circuit.
Problem 2. (25 points) For a 120-V, 1/3 hp, four pole, 1-phase induction motor, the parameters of the equivalent circuit, are R,-1.8(2, R,-2.5Ω, X,-X,-2.462, and Xm-60 Ω. At a slip of 500, the motor's rotational losses are 51W. The rotational losses maybe assumed constant over the normal operating range of the motor. If the slip is 0.05, calculate a. Input Power b. Air Gap Power, c. Induced Torque Tin d. Output power e. Load torque. f. Overall Motor efficiency g....
Q4. A six-pole, three-phase, 60 Hz induction motor is operating at a speed of 1164 rev min. The input power at this speed is 33 kW and the stator copper loss is 1200 W. Find a) Slip b Airgap power c Rotor copper loss d) Developed torque e) Developed horsepower f) If the rotational losses are 500 W, find the output torque and horsepower
5. A 208-V four-pole 60-Hz Y-connected wound-rotor induction motor is rated at 30 hp. Its equivalent circuit components are R=0.100 Ry=0.070. X - 10.00 R = 250 X; -0.2100 X=0.21002 Praw=500 W P =0.5% of input at full load For a slip of 0.05, find (a) The line current (b) The induced voltage in the rotor (c) The stator power factor (d) The rotor power factor (e) The rotor frequency (f) The stator copper losses (g) The core loss (h)...
4.6. A 460-V, 75 kW, 4-pole, delta-connected, 60-Hz, three- phase induction motor has a full-load slip of 5 percent, an efficiency of 92 percent and a power-factor of 0.87 lagging at full-load. At start-up, the motor develops 1.9 times the full load developed torque but draws 7.5 times the rated current at the rated voltage. This motor is to be started with an auto- transformer reduced-voltage starter. Assume the stator resistance and the stator core loss to be negligible. Calculate...
A three-phase 60 Hz induction motor 480 v (rms, line- to line), lo tp, spee is 12 amperes (rms), total stator Copper loss is Copper loss is 150 W, total combine with operation at the specified paramders, a) The number of Poles ! induction motor has specifications as follows R- to line), lo tp, speed is 1765 RPM, line Current stal Stator Copper loss is 140 w, total rotor is 15o W , total combined rotational loss is losw the...
5 Marks) A 4-pole, 3 phase, 50 Hz, 230 V induction motor. Each phase of rotor winding b) has one-fourth the number of turns of each stator. The full-load speed is 1,455 rpm. The rotor resistance is 0.3 Ω and rotor standstill reactance is 1.0 Ω per phase. The rotor and stator windings are similar. Stator losses are equal to 50 Watts. Friction and windage losses are equal to 30 W. Calculate ) Blocked rotor voltage per phase. 2 Marks)...