Calculate ΔE for a system that absorbs 521.0 kJ of heat from its surroundings and does 316.0 kJ of work on its surroundings. Answer should be in kj.
Solution
Mathematical statement of first law of Thermodynamics is given as,

i.e
change in internal energy is due to heat supplied to the system and work done on the system
now
when heat is absorbed by the system it is +ve ( q = +521 KJ)
when work is done on the system it is +ve ( during compression)
when work is done on the surrounding it is -ve
here work is done on the surrounding hence -ve ( W = -316 KJ )
therefore
521.0
kj +(-316kj)
= 521-316 kj
205 KJ
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