Question

Calculate the ∆Hrxn for the reaction below: MgCl2 (aq) + 2 KOH (aq) ---> Mg(OH)2 (s) + 2 KCl (aq) ∆Hfo for MgCl2 (aq) = -797.1 kJ/mol ∆Hfo for KOH (aq) =-424.2 kJ/mol ∆Hfo for Mg(OH)2 (s) = -924.7 kJ/mol ∆Hfo for KCl (aq) = -419.6 kJ/mol ∆Hrxno = ? kJ Don't forget the sign and write your 4 significant figures.

Answer 1