Question

The 10-lblb block has a speed of 4 ft/sft/s when the force of F=(8t2)F=(8t2) lblb is applied. The coefficient of kinetic friction at the surface is μμs = 0.2. Determine the speed of the block when s=42 ft.

The block is having a force applied in the same direction as the velocity. The block is moving to the right.

Answer 1

The rate of change of velocity is termed as acceleration and the rate of change of displacement is termed as velocity. For equilibrium of motions and D Almbert's principle the solution is as followsD Lambert's