A myopic person has no astigmatism, but has a near-point of 15 cm and a far point of 50 cm. Can you prescribe a single pair of glasses that will give him normal vision? this is supposed to be Ans: (-2 diopter-lens)?
in the solution I checked, their was a solution for both far and near points, but their is only one answers, so shouldn't there be only one solution
Read your question carefully...A myopic person has no astigmatism, but has a near-point of 15 cm and a far point of 50 cm. Can you prescribe a single pair of glasses that will give him normal vision?
That's why you need to calculate for two lenses.
That's what I think Buddy!!
Using lens equation: 1/f = 1/q + 1/p
For image at 25 cm and since it will be on the same side of the lens as the image at 15.
Apply 1/f = 1/p + 1/q
1/f = 1/(15) + 1/(-25)
f = 37.5 cm
Thus, power = 1/.375 = +2.668 Diopters
For the far point,
we should have images at infinity and form them at 50 cm
1/f = 0 + 1/(-50)
f = -50 cm
The dipotic power is 1/-.5 = -2.00 Diopters.
Thus, the person needs bifocals with powers of +2.67 and -2.00.
A myopic person has no astigmatism, but has a near-point of 15 cm and a far...