Question

Java.

Implement the countNotMatching method below, which takes as input a string and a character and returns how many characters in the string are NOT the supplied character. An example main method, as well as corresponding output, is supplied – you cannot change this method, and the output when the program is run must conform exactly to the sample output.

/* sample run:

Other characters: 1

Other characters: 3

Other characters: 3

*/

public static void main(String args[]) {

   System.out.printf("Other characters: %d%n", countNotMatching("Foo", 'o'));

   System.out.printf("Other characters: %d%n", countNotMatching("Bar", 'b'));

   System.out.printf("Other characters: %d%n", countNotMatching("Baz!", 'B'));

}

// put your countNotMatching method here

Answer 1

public class CountNotMatching {

    /* sample run:
    Other characters: 1
    Other characters: 3
    Other characters: 3
*/
    public static void main(String args[]) {
        System.out.printf("Other characters: %d%n", countNotMatching("Foo", 'o'));
        System.out.printf("Other characters: %d%n", countNotMatching("Bar", 'b'));
        System.out.printf("Other characters: %d%n", countNotMatching("Baz!", 'B'));
    }

    public static int countNotMatching(String s, char ch) {
        int count = 0;
        for (int i = 0; i < s.length(); i++) {
            if (s.charAt(i) != ch) {
                ++count;
            }
        }
        return count;
    }
// put your countNotMatching method here
}