Question

If the size of an integer is 8 bytes, and an address (pointer) needs 4 bytes, what will be the output of the program?

#include<stdio.h>

int main()

{

    int arr[] = {12, 13, 14, 15, 16};

    printf("%d, %d, %d\n", sizeof(arr), sizeof(*arr), sizeof(arr[0]));

    return 0;

}

A		20, 4, 4
B		40, 4, 8
C		20, 2, 4
D		4, 4, 4

Answer 1

Option A) 20,4,4