Question

Suppose you place 1.200 mol of N2 and 3.600 mol of H2 into a 2.00 L flask and allow the reaction to come to equilibrium. What is the composition of the equilibrium mixture if you obtain 0.096 mol of NH3 from it? Then, calculate KC!

HINT: Set up an ICE table! N2 (g) + 3 H2 (g) -----2 NH3 (g)

Answer 1