Question

1) A woman who is heterozygous for an X-linked recessive disease gene has many children with...

1) A woman who is heterozygous for an X-linked recessive disease gene has many children with a man who has the disease (assume the disease is due to a single gene). Which answer below will most likely describe the phenotypes of their children?

A) all the sons will be normal all the daughters will be carriers

B) all the sons will be carriers all the daughters will be normal

C) all the sons will be normal and all the daughters will have the disease

D) half the sons will have the disease and half the daughters will be normal

4) A woman with blood type A marries a man with blood type B. The woman's parents are blood type AB and O. The man's parents are both blood type B, but he has a full sister that has blood type O (full sister, means that she's not a half sister, she shares both parents with the man). Given this information, what is the probability that the woman and the man will have a daughter, and that this daughter will have blood type A?

A) 1/4

B) 1/12

C) 1/8

D) 1/6

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Answer #1

1) let assume the defected gene is a

then the genotype of woman will be XaXand the man will have XaY

XaX    X XaY

Xa

X

Xa

Xa Xa

daughter with disease

XaX

daughter, carrier

Y

XaY

son with disease

XY

son, normal

D) half the sons will have the disease and half the daughters will be normal

4) let start with the genotype of the full sister of the man. She has O blood group, thus the genotype= IoIo

Now, both the parent of the man has blood group B. Now looking at their daughter, both the parent must have carried one Io. Thus the genotype of the parent is IBIo

The man is having the blood group B, looking at the genotype of his parent which is IBIo for both

IBIo X IBIo

there are two possibility, the man either have IBIo orIBIB

Now coming to the woman, her parents are having AB and O blood group. Thus the genotype of her parent is IA IB for AB and IoIo for for O blood group.

As the woman is A, her genotype will be IAIo.

when we crossed IA Io X IB IB

there will have no daughter with A blood group

IA

Io

IB

IA IB

AB

Io IB

B

IB

IA IB

AB

Io IB

B

however if the cross is between IAIo. X IBIo

there is a possibility of A) 1/4 daughter will have blood group tyoe A

IA

Io

IB

IA IB

AB

IB Io

B

Io

IA Io

A

Io Io

O

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