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Calculate the lattice energy of CaBr2

Calculate the lattice energy of {rm{CaBr}}_2knowing that:
The standard heat of formation of{rm{CaBr}}_2 is -675 {{rm{kJ}}}/{{rm{mol}}}.
The first ionization energy of {rm Ca} is 590 {{rm{kJ}}}/{{rm{mol}}} anditssecond ionization energy is 1145 {{rm{kJ}}}/{{rm{mol}}}.
The heat of sublimation of {rm{Ca}};[{rm{Ca}}(s); rightarrow ;{rm{Ca}}(g)] is 178 {{rm{kJ}}}/{{rm{mol}}}.
The bond energy of {rm{Br}}_2 is 193{{rm{kJ}}}/{{rm{mol}}},
the heat of vaporization of {rm{Br}}_2 (l)is 31 {{rm{kJ}}}/{{rm{mol}}},
and the electron affinity of {rm Br} is -325 {{rm{kJ}}}/{{rm{mol}}}.



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