Question

Q1. You have the following address: 192.16.5.133/29. How many total bits are being used to identify the network, and how many total bits identify the host?

Q2. You currently use the defaul mask for your IP network 192.168.1.0. You need to subnet your network so that you have 30 additional networks, and4 hosts per network.Is this possible, and what subnet mask should you use?

Q3. You are still using the default mask for your IP network 192.168.1.0. You need to subnet your network so that you have 5 additional networks, and 60 hosts pernetwork. Is this possible, and what subnet mask should you use?

Q4. You have sub-netted your class C network 192.168.1.0 with a subnet mask of 255.255.255.240. Please list the following: number of networks, number of hosts pernetwork, the full range of the first three networks, and the usable address range from those first three networks.

Q5. You have sub-netted your class C network 200.138.1.0 with a subnet mask of 255.255.255.252. Please list the following: number of networks, number of hosts pernetwork, the full range of the first three networks, and the usable address range from those first three networks. Additionally, identify the broadcast address foreach of the first three networks.

Answer 1

Dear user,Note: One question per one post regarding cramster rules.
So, please post one question at a time.Q1)Given address: 192.16.5.133/29Where the /29 notation indicates that the leftmost 29 bits of the 32-bit quantity define the subnet address.So, 29 bits are being used to identify the network.The subnet 192.16.5.133/29 conists of the 3 host interfaces (192.16.5.133,192.16.5.134,192.16.5.135).So, total bits identify the host=3Q2)Given data,Use the defaul mask for your IP network 192.168.1.0. You need to subnet your networkso that you have 30 additional networks, and4 hosts per network.YES, it is possible.The subnet 192.168.1.0 consists of the subnet masks, deteach each interface from its host.Then the using subnet mask is 255.255.255.248Q3)No, it is not possible.