vector addition help
If a hook can sustain a maximum withdrawal force of 250 N inthe vertical direction, determine the maximum tension, T, that can be exerted.
the vector T, points down in the fourth quadrant with the inside angle at 10 degrees.
Homework Answers
It isn't clear what is meant by "the inside angle is 10 deg" so we will solve this both ways.
If the force is mainly sideways, only a small component is down and we can have a tension much larger than 250N. Sin(10) is very small
T sin(10) can be no more than 250N
T = 250N/sin(10) = 1,440N
The other way to interpret "the inside angle is 10 deg" would be that the tension is almost straight down. If this is what the question is asking,most of the force is vertical and we can only pull with a little bit morethan 250N. Cos(10) is almost at its maximum, so this is what we use inthis case.
T cos(10) can be no more than 250N
T = 250N/cos(10) = 254N
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