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torque

uploaded imageThe body in Fig.10-37 is pivoted at O. Three forces act on it in the directions shown: FA = 8.5 N at point A, 9.8 m from O; FB = 14 N at point B, 2.6 m from O; and FC = 20 N atpoint C, 4.9 m from O. Taking the clockwise direction to be negative, what is the net torque about O?

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Answer #1
From the given figureOA = 9.8 mFA = 8.5 NτA = OA FA sin135 = 58.9 NmOB = 2.6 mFB = 14 NτB = OB FB sin(-90) =-36.4 NmFC = 20 NOC = 4.9 mτC = OC FC sin160 = 33.51 NmNet torque τ = τA + τB + τC = 58.9 - 36.4 + 33.51 =56 Nm
answered by: Hieu Chu
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